Question

express [1 (+-) 2sinx cosx] as a perfect square.

Answer 1

Answer:

1+2sinθcosθ = sin²θ + cos²θ + 2sinθcosθ = (sinθ + cosθ)²

Step-by-step explanation:

Answer 2

( sinx + cosx )^2

using identity ((a+b)^2. = a^2 +b^2+2ab)

= sin^2x + cos^2x + 2sinxcosx

(using identity (sin^2 + cos^2=1))

1+2sinxcosx