Question

Express 192

as the sum of two consecutive integers.​

Answer 1

Answer:

Let the two consecutive integers be $x$  and  $x+1$

Given,

       Sum = 192

       $x + (x+1) = 192$

       $x +x+1 = 192$

       $2x = 192 -1$

       $2x = 191$

       $x= \frac{191}{2}$

       $x = 95.5$

∴ The two numbers are 95.5 & (95.5 + 1)

i.e)  The two consecutive integers are 95.5 & 96.5

                Hope it helps you^_^

Answer 2

Answer:

the two consecutive integers are 95.5 and 96.5

Step-by-step explanation:

let the two integers be x and (x + 1)

∴ x + (x + 1) = 192

x + x + 1 = 192

2x + 1 = 192

2x = 192 - 1

2x = 191

x = $\frac{191}{2}$

∴ x = 95.5

(x + 1) = 95.5 + 1

∴ (x + 1) = 96.5

∴ the two consecutive integers are 95.5 and 96.5

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