express (3+4i)×(3-4i) in the form of a +ib?
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0
Answer:
(3+4i)×(3-4i)
7i × -1i
-7i
i = -7
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Answered by
0
Answer:
by a2-b2=(a+b)(a-b)
3^2-(4i)^2
i^2=-1
so,
9+16=25
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