Math, asked by geethab2530, 6 hours ago

write the solution for the equation x^2 +x-2=0 in roster
form​

Answers

Answered by talpadadilip417
0

Step-by-step explanation:

 \mathtt{x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }

 \mathtt{x =   \frac{ - 1 \pm \sqrt{ {1}^{2}  - 4 \times 1 \times ( - 2)} }{2 \times 1} }

 \mathtt{x =  \frac{ - 1 \pm \sqrt{1 + 8} }{2} }

 \mathtt{x =   \frac{ - 1 \pm \sqrt{9} }{2} }

 \mathtt{x =   \frac{ - 1 \pm3}{2} }

 \mathtt{x =  \frac{2}{2} \quad \quad \: or \quad x =  -  \frac{4}{2}  }

 \mathtt{x = 1 \quad \quad \: or \:  \quad \quad \: x =  - 2}

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