Express 4√1250 in its simplest form.
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Answered by
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Hi ,
i think it is forth root of 1250 or 4√1250
I answer both questions .
1 ) forth root of 1250 = ( 1250 ) ^ 1/4
expressing 1250 into product of prime
= ( 5 × 5 × 5 × 5 × 2 ) ^ 1/4
= ( 5^4 × 2 ) ^ 1/4
= ( 5^4 )^ 1/4 * ( 2 )^ 1/4 [ ∵ ( ab )^m = a^m × b^n ]
= 5 × ( 2 )^1/4 [ ∵ ( a^m ) ^n = ^mn ]
2 ) 4 √(1250) = 4 √ [(5 × 5 ) × ( 5 × 5 ) × 2 ]
= 4 × 5 × 5 × √2
= 100√2
I hope this helps you .
i think it is forth root of 1250 or 4√1250
I answer both questions .
1 ) forth root of 1250 = ( 1250 ) ^ 1/4
expressing 1250 into product of prime
= ( 5 × 5 × 5 × 5 × 2 ) ^ 1/4
= ( 5^4 × 2 ) ^ 1/4
= ( 5^4 )^ 1/4 * ( 2 )^ 1/4 [ ∵ ( ab )^m = a^m × b^n ]
= 5 × ( 2 )^1/4 [ ∵ ( a^m ) ^n = ^mn ]
2 ) 4 √(1250) = 4 √ [(5 × 5 ) × ( 5 × 5 ) × 2 ]
= 4 × 5 × 5 × √2
= 100√2
I hope this helps you .
Answered by
1
100√2 is the answer of this question
karthikjr2016:
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