Question

Express 6 square as the sum of consecutive odd numbers

Answer 1

Answer:

Step-by-step explanation:

6 ^ 2 = 36 = 5 + 7 + 11 + 13

= 1 + 3 + 15 + 17

= 3 + 5 + 11 + 17

= 3 + 5 + 13 + 15

= 1 + 7 + 13 + 15

but as consecutive odd integers, i do not Think you can.

Answer 2

Step-by-step explanation:

To find : Express 6 square as the sum of consecutive odd numbers ?

Solution :

Square of 6 is $6^2=36$

The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...

Now, we write the sum of consecutive odd numbers as

$36 = 5 + 7 + 11 + 13$

$36= 1 + 3 + 15 + 17$

$36= 3 + 5 + 11 + 17$

$36= 3 + 5 + 13 + 15$

$36= 1 + 7 + 13 + 15$

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