Express all the trigonometric ratio in the form of cotA ?
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using the identity cosec²A-cot²A=1
we get cosec²A=1+cot²a
1/sin²A=1+cot²A
sinA=1/√(1+cot²A)
tanA=1/cotA
cosA=sinA*cotA
cosA=cotA//√(1+cot²A)
tanA=1/cotA
we get cosec²A=1+cot²a
1/sin²A=1+cot²A
sinA=1/√(1+cot²A)
tanA=1/cotA
cosA=sinA*cotA
cosA=cotA//√(1+cot²A)
tanA=1/cotA
kinkyMkye:
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