Express all trigonometric ratio in term of sintita
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there you go :-
cos a = square root of (1- square of sin a)
tan = sin a / cos a = sin a/(square root of (1- square of sin a))
cosec a = 1/sin a
sec a = 1/cos a = 1/(square root of (1- square of sin a))
cot a = cos a /sin a = (square root of (1- square of sin a))/sin a
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cos a = square root of (1- square of sin a)
tan = sin a / cos a = sin a/(square root of (1- square of sin a))
cosec a = 1/sin a
sec a = 1/cos a = 1/(square root of (1- square of sin a))
cot a = cos a /sin a = (square root of (1- square of sin a))/sin a
PLEASEEEEEEE MARK ME AS BRAINLIST
Answered by
2
Here we go........
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