Math, asked by aymanhaseeb4807, 1 year ago

Express all trigonometric ratio in term of sintita

Answers

Answered by joy6950
2
there you go :- 
cos a = square root of (1- square of sin a) 
tan = sin a / cos a = sin a/(square root of (1- square of sin a)) 
cosec a = 1/sin a 
sec a = 1/cos a = 1/(square root of (1- square of sin a)) 
cot a = cos a /sin a = (square root of (1- square of sin a))/sin a

PLEASEEEEEEE MARK ME AS BRAINLIST
Answered by abhinash49
2
Here we go........

 \sin( \alpha )   =  \frac{1}{ \csc( \alpha ) }  \\  \\  \sin( \alpha )  =  \sqrt{1 -  { \cos( \alpha ) }^{2} }  \\  \\  \sin( \alpha )  =  \cos( \alpha )  \times  \tan( \alpha )  \\  \\  \sin( \alpha )  =  \cot( \alpha )  \times  \cos( \alpha )  \\  \\  \sin( \alpha )  =  \cos(90 -  \alpha )  \\  \\  \sin( \alpha )  =  \frac{perpendicular}{hypotenuse}  \\  \\ hope \: help
Similar questions