Question

Express each number as a product of its prime factors
a.140
b.156
c.3825
d.5005
e.7429

Answer 1

Answer:

a.)140=2×2×5×7

b.)156=2×2×3×13

c.)3825=3×3×5×5×17

d.)5005=5×7×11×13

e.)7429=17×19×23

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

(i) 140

By Taking the LCM of 140, we will get the product of its prime factor.

Therefore,

• 140 = 2 × 2 × 5 × 7 × 1 = 22 × 5 × 7

(ii) 156

By Taking the LCM of 156, we will get the product of its prime factor.

Hence,

• 156 = 2 × 2 × 13 × 3 × 1 = 22 × 13 × 3

(iii) 3825

By Taking the LCM of 3825, we will get the product of its prime factor.

Hence,

• 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32 × 52 × 17

(iv) 5005

By Taking the LCM of 5005, we will get the product of its prime factor.

Hence,

• 5005 = 5 × 7 × 11 × 13 × 1 = 5 × 7 × 11 × 13

(v) 7429

By Taking the LCM of 7429, we will get the product of its prime factor.

Hence,

• 7429 = 17 × 19 × 23 × 1 = 17 × 19 × 23