Question

Express each of the following perfect square as sum of the odd number 676

Answer 1

Answer:

337+339=676

Step-by-step explanation:

Given number = 676

It can be written as= 26 square

the general form of an odd number =2n+1

the sum of two odd numbers =676

2n+1+2n+3=676

=>4n+4=676

=>4(n+1)=676

=>n+1=676/4

=>n+1=169

n=169-1

therefore n=168

now the odd numbers are

2n+1=2(168)+1=336+1=337

2n+3=2(168)+3=336+3=339

therefore 337+339=676

Answer 2

337+339=676

Step-by-step explanation:

Given number = 676

It can be written as= 26 square

the general form of an odd number

=2n+1

the sum of two odd numbers =676

2n+1+2n+3=676

=>4n+4=676

=>4(n+1)=676

=>n+1=676/4

=>n+1=169

n=169-1

therefore n=168

now the odd numbers are

2n+1=2(168)+1=336+1=337

2n+3=2(168)+3=336+3=339

therefore 337+339=676