Express each of the following perfect square as sum of the odd number 676
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Answered by
0
Answer:
337+339=676
Step-by-step explanation:
Given number = 676
It can be written as= 26 square
the general form of an odd number =2n+1
the sum of two odd numbers =676
2n+1+2n+3=676
=>4n+4=676
=>4(n+1)=676
=>n+1=676/4
=>n+1=169
n=169-1
therefore n=168
now the odd numbers are
2n+1=2(168)+1=336+1=337
2n+3=2(168)+3=336+3=339
therefore 337+339=676
Answered by
8
337+339=676
Step-by-step explanation:
Given number = 676
It can be written as= 26 square
the general form of an odd number
=2n+1
the sum of two odd numbers =676
2n+1+2n+3=676
=>4n+4=676
=>4(n+1)=676
=>n+1=676/4
=>n+1=169
n=169-1
therefore n=168
now the odd numbers are
2n+1=2(168)+1=336+1=337
2n+3=2(168)+3=336+3=339
therefore 337+339=676
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