express in a + ib if x = (√2 + √3i) + (√2 - √3i) / (√3 + √2i ) + √3 - √2i )
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Step-by-step explanation:
we have x=(√2 + √3i) + (√2 - √3i) / (√3 + √2i ) + (√3 - √2i )
=(√2 + √3i+ √2 - √3i) / (√3 + √2i + √3 - √2i )
=2√2 / 2√3
= √2/√3
because the imaginary part here is zero
so if we express it in a+ib then
a+ib = (√2/√3) + 0i
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