express in the form of a+ib
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(1+i)^4/(1-i)^4
=(1+i^2+2i)^2/(1+i^2-2i)^2
={1+(-1)+2i}^2/{1+(-1)-2i}^2
=(2i)^2/(-2i)^2
=4i^2/4i^2
=1
so, in the form of a+ib is
1+0.i
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