Question

Express of the following as the sum of consecutive integers
A) 21^2

Answer 1

Answer:

let one integer be x

since the integers are consecutive,

other integer = x + 1

Now,

a) (x) + (x + 1) = 21²

2x + 1 = 441

2x = 440

x = 440/2 = 220. and x+1 = 221

So,

the integers are 220 and 221

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Answer 2

Step-by-step explanation:

LET ONE INTEGER BE X

THEN OTHER WILL BE (X+1).

$x + (x + 1) = {21}^{2} \\ 2x + 1 = 441 \\ 2x = 440 \\ x = 220$

one number is 220

other number is 221