Question

Express sec 79 degrees + cot 79 degrees in terms of trigonometric ratios of angle between zero degree and 45 degree​

Answer 1

$=cosec11^{\circ}+tan11^{\circ}$

Step-by-step explanation:

$sec79^{\circ}+cot79^{\circ}$

$=sec\left ( 90-11 \right )^{\circ}+cot\left ( 90-11 \right )^{\circ}$

$=cosec11^{\circ}+tan11^{\circ}$

Use trigonometry conversion formula

$sec\left ( 90^{\circ}-\Theta ^{\circ} \right )=cosec\Theta ^{\circ}$

$cot\left ( 90^{\circ}-\Theta ^{\circ} \right )=tan\Theta ^{\circ}$

Answer 2

Answer:

Sec 79° + Cot 79°

|———————————–|

| Sec(90-Ø)= Cosec Ø. |

|Cot(90-Ø)=Tan Ø. |

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Sec (90-11) + Cot(90-11)

=Cosec 11° +Tan 11°