Question

Express sec 79° + for 79° in terms of trigonometric ratios of angles between 0° and 45°​

Answer 1

Answer:

COSEC 21 DEGREE + TAN 21 DEGREE

STEP BY STEP EXPLANATION :

GIVEN ,SEC 79 DEGREE + COT 79 DEGREE.

SO ,SEC 79 =COSEC 21..

AND COT 79 = TAN 21.

THUS , EXPRESSED .

HOPE THIS WILL HELP U A LOT..

Answer 2

Express  $\sec79+\cot 79$ in terms of  trigonometric ratios  of angles between 0° and 45​° is $\csc 11+\tan 11$.

Step-by-step explanation:

We have,

$\sec79+\cot 79$

To express  $\sec79+\cot 79$ in terms of  trigonometric ratios  of angles between 0° and 45​°.

∴ $\sec79+\cot 79$

= $\sec (90-11)+\cot (90-11)$

Using the trigonometric identity,

$\sec (90-A)=\csc A$ and

$\cot (90-A)=\tan A$

= $\csc 11+\tan 11$

∴ $\sec79+\cot 79$ = $\csc 11+\tan 11$

Thus, express  $\sec79+\cot 79$ in terms of  trigonometric ratios  of angles between 0° and 45​° is $\csc 11+\tan 11$.