Express( sin 135°-i cos 135°) in polar form
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The required complex number, z =
Step-by-step explanation:
Let z = ( 135°-i 135°)
To express ( 135°-i 135°) in polar form = ?
We know that,
The complex number in polar form:
z =
∴ 135° = = and
135° =
∴ z = ( 135°-i 135°)
=
Multiplying numerator and denominator by , we get
=
Thus, the required complex number, z =
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