Express sin A and sec A in terms of cot A
Answers
Answered by
7
sin = 1/cosecA
= 1/√cosec²A
= 1/√(1+cot²A)
sec A = √1+tan²A
= √1+1/cot²A
= √(cot²A+1/cot²A)
= √(cot²A+1)/cotA
= 1/√cosec²A
= 1/√(1+cot²A)
sec A = √1+tan²A
= √1+1/cot²A
= √(cot²A+1/cot²A)
= √(cot²A+1)/cotA
Answered by
2
sinA =1/cosec A
=1/1+cot2A
SecA=tan2A-1
=1/cot2A -1
=1/1+cot2A
SecA=tan2A-1
=1/cot2A -1
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