Question

Express Sin A in terms of other trigonometric ratios​

Answer 1

Answer:

Step-by-step explanation:

There you go :-

Cos a = square root of (1-square of sin a)

tan = sina/cosa = sin a/(square root of (1-square of sina))

Cosec a= 1/sin a

Sec a = 1/cos a= 1/(square root of (1-square of sin a))

Cot a = cos a/sina = (square root of (1-square of sin a))/sin a

Hope it will help you :-) :-)

Answer 2

Step-by-step explanation:

Given that:- Sin A

1) Cosec A =1/SinA

=>SinA= 1/ Cosec A

2) we know that Sin² A + Cos ² A=1

=>Sin² A=1- Cos² A

=>Sin A= √(1-Cos²A)

3)We know that Cosec² A- Cot² A=1

=>Cosec²A=1+Cot² A

=>Cosec A=√(1+Cot²A)

=>1/Sin A=√(1+Cot²A)

=>Sin A=1/√(1+Cot²A)

4)Sin A =1/√(1+1/tan²A)

=>Sin A= 1/√[(tan²+1)/tan²A]

=>Sin A = √[(tan²A/(tan²+1)]

=>Sin A=tan A/(√tan²A+1)

5)sinA = √(1-Cos² A)

=>Sin A=√[(1-(1/sec² A)]

=>Sin A= √[(Sec² A-1)/Sec² A]

=>Sin A = √(Sec² A-1)/sec A