Question

how many two digit number that increases by 75% where their digits are reserved​

Answer 1

Answer:

let th no. be 10x+y

A/Q

10x+y+75%of (10x+y)=10y+x

10x+y+3/4(10x+y)=10y+x

40x+4y+30x+3y=10y+x

40x+4y+30x+3y=40y+4x

70x+7y=40y+4x

70x-4x=40y-7y

66x=33y

x/y=33/66

x/y=1/2.

Step-by-step explanation:

let the ten digit no be x

and one digit be y

thus original no. = 10x+y

after reversing the digit,

the new digit= 10y+x

A/Q

original number +75%of original no. = new no.

10x+y+ 3/5(10x+y)=10y+x

and answer become 1/2

after solved