express sin a ,tan a and cosec a in terms of sec a
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sin a= under root sec^2 a -1/sec^2 a
tan a= under root sec^2 a -1
cosec a=1/sin a
tan a= under root sec^2 a -1
cosec a=1/sin a
adharsh3:
could you please show the process??
yaa Sin^2 a+Cos^2 a= 1 and cos a=1/sec a
if understood mark as brainliest
where's remaining
thanks bro.
1+tan^2 a=sec^2 a
and cosec is 1/sin a so put value of sin a from above
thanks yaar
Answered by
6
SinA=√(sec^2A-1)/secA
TanA=√(sec^2A-1)
CosecA=secA/√(sec^2A-1)
Please mark as brain list answers
TanA=√(sec^2A-1)
CosecA=secA/√(sec^2A-1)
Please mark as brain list answers
show the process
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