Question

if secA+tanA=p, prove p^2-1/p^2+1

Answer 1

see that photo I hope u understand

Answer 2

heya ✔
✖first of all ur question is incorrect..

question should be secA+tanA=p,,,then proove sinA=p^2-1/p^2+1

then .

secA+tanA=p.-----1)

1/secA+tanA*secA-tanA/tanA+SecA 【multiplied by secA-tanA on numerator and denominator 】

•and secA-tanA/sec^2-tan^2A =1/p

✔so, secA-tanA=1/p
【you know sec^2A-tan^2A=1 here applied 】
+--------2)

✔now subtracting 2 from 1) we get.

secA+tanA-sec +tanA=p-1/p

=>2tanA=p^2-1/p-----3)

and similarly ...
when adding 1 )and 2) we get..

2secA=p^2+1/p-----4)

now,dividing 3)and 4) we get..

2tanA/2secA=p^2-1/p^2+1

sinA=p^2+1/p^2+1..
Ans.....

@Rajukumar☺☺☺