Question

express sin5A-sin3A as a product

Answer 1

Answer:

2 sinA.cos4A

Step-by-step explanation:

sin5A-sin3A

on Using the following identity,

sinA-sinB= 2 sin[(1/2)(A-B)] cos[(1/2)(A+B)]

we get Sin5A - Sin3A = 2 sin[(1/2)(5A-3A)].cos[(1/2)(5A+3A)]

                                    = 2 sin [ 2A/2 ] . cos [8A/2]

                                    = 2 sinA.cos4A