Express sin67+cos 75 in terms of trignometruc ratios of agles between 0 and 45
Answers
Answered by
2
Answer: cos 23 + sin 15
sin 67 = cos (90 -67) = cos 23 [sin A = cos (90 - A) and cos A = sin (90 - A)]
cos 75 = sin(90-75) = sin 15
Answered by
1
Answer:
your answer....
Step-by-step explanation:
sin67+cos75
=sin(90-67)+cos(90-75)
=cos23+sin15
Ans
cos A = 23 and sin= 15
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