Question

express tan theta in terms of sin theta???? answer this its vry important!!

Answer 1

Answer:

$tan\theta =\frac{sin\theta}{\sqrt{1-sin^{2}\theta}}$

Step-by-step explanation:

$tan\theta =\frac{sin\theta}{cos\theta}\\=\frac{sin\theta}{\sqrt{1-sin^{2}\theta}}$

Therefore,

$tan\theta =\frac{sin\theta}{\sqrt{1-sin^{2}\theta}}$

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