Express tanA in terms of cosA
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4
TanA=sinA/cosA..........
Answered by
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Hey
here is your answer !!
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sin^2x + cos^2x = 1
divide each term by cos^2x
sin^2x / cos^2x + cos^2x/cos^2x = 1/cos^2x
tan^2x + 1 = 1 /cos^2x
tan^2x = 1/cos^2x - 1
tan^2x = 1 - cos^2x /cos^2x
tan x = √ 1 - cos^2x / cos^2x
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hope it helps
here is your answer !!
-------------------------------
sin^2x + cos^2x = 1
divide each term by cos^2x
sin^2x / cos^2x + cos^2x/cos^2x = 1/cos^2x
tan^2x + 1 = 1 /cos^2x
tan^2x = 1/cos^2x - 1
tan^2x = 1 - cos^2x /cos^2x
tan x = √ 1 - cos^2x / cos^2x
----------------------------
hope it helps
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