Question

Express the complex number 2-i/(1-i)(1+2i) in the form a+ib​

Answer 1

Answer:

0+2i

Step-by-step explanation:

=2-i/(1-i)(1+2i)

=2-i/(1)^-(i)^

=2-i/1+1

=2-i/2*-2/-2

=4-2i/-4

=-(4+2i)/-4

=4+2i/4. :-and - cancels

=2i. : 4and 4 cancels

=0+2i it of the form a+ib

I hope it will help you

Answer 2

Answer:

1/2 -1/2i

Step-by-step explanation:

$\frac{2 - i}{(1 - i)(1 + 2i) } \\ = \frac{2 - i}{1 + 2i - i + 2}$

$\frac{2 - i}{3 + i} \\ = \frac{(2 - i)(3 - i)}{(3 + i)(3 - i)}$

$\frac{6 - 2i - 3i - 1}{10} \\ = \frac{5 - 5i}{10}$

$= \frac{1}{2} - \frac{1}{2} i$

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1. Simplify by DISTRIBUTIVE METHOD.
2. RATIONALISE with the denominator's conjugate.
3. Simplify and put it in the form a+ib.
4. and... remember, in case of complex number, (a+b)(a-b) = a^2+b^2.

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Hope it helps.....!

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