Express the coulombs law of forces between charges at rest in SI units
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The formula is --
F = k q₁q₂/r²
Here Unit of k = Nm²C⁻²
Unit of q₁q₂ = C x C = C² (coulomb)
r² = m² ( sq meter)
Unit of F = N (Newton)
So plugging the units only,
F = Nm² C⁻² x C² / m²
Here m² gets cancelled in both numerator and denominator and C⁻² x C² = C⁻²⁺² = C⁰ = 1
Now,
F = N x 1
F = N (Newton)
Hope This Helps You!
F
F = k q₁q₂/r²
Here Unit of k = Nm²C⁻²
Unit of q₁q₂ = C x C = C² (coulomb)
r² = m² ( sq meter)
Unit of F = N (Newton)
So plugging the units only,
F = Nm² C⁻² x C² / m²
Here m² gets cancelled in both numerator and denominator and C⁻² x C² = C⁻²⁺² = C⁰ = 1
Now,
F = N x 1
F = N (Newton)
Hope This Helps You!
F
Answered by
5
Answer:
The force of attraction or repulsion between two stationary point charges is
(i) directly proportional to the product of the magnitude of two charges.
(ii) inversely proportional to the square of the distance between them.
This force acts along the line joining the two charges.
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