Question

Find the angle whose complement is one-third of its supplement

Answer 1

let angle be x.
then (90-x)=1/3(180-x)
270-3x=180-x
270-180=-x+3x
90=2x
x=45°

Answer 2

Let the angle be 'x°'

Then complement of that angle -- (90- x)°
Supplement of that angle -- (180 - x)°

A/Q ---.>

90 - x = 1/3( 180 - x)
90 - x = 60 - x/3
-x + x/3 = 60 - 90
[ - 3x + x] / 3 = - 30
-2x/3 = -30
x = 30 x 3/2
x = 45°

The required angle is 45°

Hope This Helps You!