Question

express the following as a single log 1/3log27-2log1/3​

Answer 1

Step-by-step explanation:

a, b > 0# then:

#log ab = log a + log b#

and

#log (a/b) = log a - log b#

Hence:

#log a^n = n log a" "# for any integer #n > 0#

So we find:

#1/2 log 9 + 2 log 6 + 1/4 log 81 - log 12#

#=1/2 log 3^2 + 1/4 log 3^4 + log 6^2 - log 12#

#=1/2 (2 log 3) + 1/4 (4 log 3) + log (36/12)#

#= log 3 + log 3 + log 3#

#= 3 log 3#

hope it helps you

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Answer 2

Answer:

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