Question

Express the following as algebraic equation and solve:

a) Twice a number increased by 6 is 101. What is the number?
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Answer 1

Let the required number be x.

Given,

Twice a number increased by 6 is 101

ATQ,

$= > 2x + 6 = 101 \\ = > 2x = 101 - 6 \\ = > 2x = 95 \\ = > x = \frac{95}{2}$

Therefore,the required number is 95/2.