Math, asked by avenger1403, 7 months ago

express the following complex number in the standard form a+ib:​

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Answers

Answered by ravi2303kumar
0

Answer:

-\sqrt{3} +i

Step-by-step explanation:

[ (1+i) ( 1+\sqrt{3}i) ] / (1-i)

= [ (1+i) ( 1+\sqrt{3}i) ] / (1-i)  x (1+i)*(1-i)

=  [ (1+i)² ( 1+\sqrt{3}i) ] / (1²-i²)

=  [ (1²+2(1)(i)+i²) ( 1+\sqrt{3}i) ] / (1-(-1))

=  [ (1+2i+(-1)) ( 1+\sqrt{3}i) ] / (1+1))

=  [ (2i) ( 1+\sqrt{3}i) ] / 2)

= (i) ( 1+\sqrt{3}i)

= ( i(1) +  \sqrt{3}i(i) )

= -\sqrt{3} +i

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