Question

express the following function as ordered pairs and determine its range f:x belongs to R, f(x) x3 +1 where x= {-1,0,3,9}​

Answer 1

Step-by-step explanation:

We have, f:X→ R,flx) = x3 + 1.

Where X = {-1, 0, 3, 9, 7}

Now f (-l) = (-l)3+1 =-l + 1 =0

f(0) = (0)3+l=0+l = l

f(3) = (3)3 + 1 = 27 + 1 = 28

f(9) = (9)3 + 1 = 729 + 1 = 730

f(7) = (7)3 + 1 = 343 + 1 = 344

f= {(-1, 0), (0, 1), (3, 28), (9, 730), (7, 344)}

Range of f= {0, 1, 28, 730, 344}