Question

express the following in the form of x+iy (i) (2-3i)(3+4i)​

Answer 1

(3+4i)

(2−3i)

Multiplying both numerator and denominator by the Complex conjugate of the denominator

Therefore,

(3+4i)

(2−3i)

=

3+4i

2−3i

×

3−4i

3−4i

=

(3)

2

−(4i)

2

(2−3i)(3−4i)

=

9+16

(6+12i

2

)−(9+8)i

=

25

−6−17i

=

25

−6

+

25

−17

i

Here, A=

25

−6

and B=

25

−17