Question

Express the following in the terms of a+ib

(-i)(2i)(-1/8i)³

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Answer 1

Answer:

this the answer

Step-by-step explanation:

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Answer 2

Answer:

Here , ${i}^{2} = ( - 1) \: </strong><strong>,</strong><strong>\: {i}^{3} = (- i)$

$( - i)(2i)( \frac{ - 1}{8i} ){}^{3} \\ \\ = (- {i}^{2} )( 2) \times \frac{ - 1}{8 {}^{3}i {}^{3} } \\ \\ = 2 \times \frac{ - 1}{512 \times ( - i)} \\ \\ = \frac{1}{256i} \\ \\ multiply \: i \: in \: denominator \: and \: numerator \\ \\ = \frac{1}{256i} \times \frac{i}{i} \\ \\ = \frac{ - i}{256} \\ \\ = 0 + i( \frac{ - 1}{256} ) = a + ib$