Math, asked by shivashanka, 6 months ago

Express the following statements as a linear equation in two variables.

i) The sum of two numbers is 50

ii) Ramesh and Suresh contributed `.1500/- towards an orphanage

iii) Ravi got 5 more marks than double the marks of Raju

iv) Cost of 10 pens and 5 pencils is `.125/-

v) Radha's age is 3 times the age of Rajini​

Answers

Answered by nayinikoti
2

Answer:

the sum of two numbers is 50 option A

Step-by-step explanation:

I hope it helps

Answered by PoojaBurra
1

Given,

i) The sum of two numbers is 50

ii) Ramesh and Suresh contributed `.1500/- towards an orphanage

iii) Ravi got 5 more marks than double the marks of Raju

iv) Cost of 10 pens and 5 pencils is `.125/-

v) Radha's age is 3 times the age of Rajini​

To Find,

Express the following statements as a linear equation in two variables.

Solution,

We can solve the question as follows:

i) The sum of two numbers is 50

Let the first number be x and the other number be y.

First\: number = x\\Other\: number = y

Their sum is equal to 50.

Answer: x + y = 50

ii) Ramesh and Suresh contributed 1500/- towards an orphanage

Let the money contributed by Ramesh be x and the money contributed by Suresh be y.

Money\: contributed\: by Ramesh = Rs.\: x\\Money\: contributed\: by Suresh = Rs.\: y

The total money contributed by both of them is Rs. 1500.

Answer: x + y =Rs.\: 1500

iii) Ravi got 5 more marks than double the marks of Raju

Let Raju's marks be x and Ravi's marks be y.

Raju's\: marks = x

Ravi's\: marks = y

Ravi's marks are five more than double the marks of Raju.

Answer: y = 2x + 5

iv) Cost of 10 pens and 5 pencils is 125/-

Let the cost of one pen be Rs. x and the cost of one pencil be Rs. y

Then,

Cost\: of\: 10\: pens = 10x\\Cost\: of\: 5\: pencils = 5y

The total cost is equal to Rs. 125.

Answer: 10x + 5y = Rs.\: 125

v) Radha's age is 3 times the age of Rajini​

Let Rajini's age be x and Radha's age be y.

Rajini's\: age = x\\Radha's\: age = y

Radha's age is 3 times the age of Rajini's.

Answer: y = 3x

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