express the hcf of 235 and 365 as 235x+365y, where x and you are integers
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Answered by
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Step-by-step explanation:
Given -
- Numbers 235 and 365
To Find -
- HCF and express it in the form of 235x + 365y, where x and y are integers
Now,
235 = 5×47
365 = 5×73
→ HCF = 5
Now, Expressing 5 in the form of 235x + 365y, we get :
→ 235x + 365y = 5
→ 5(47x + 73y) = 5
→ 47x + 73y = 1
→ 47(2) + 73(-1) = 1
→ 74 - 73 = 1
→ 1 = 1
Hence,
The value of x is 2 and value of y is -1
Answered by
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- Number 235 and 365
- Hcf of 235 and 365 as 235x+365y, where x and you are integers.
235 = 5 × 47
365 = 5 × 73
235x + 365y = 5
5(47x + 73y) = 5
47x + 73y = 1
47(2) + 73(-1) = 1
74 - 73 = 1
1 = 1
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