Question

Express the (-i)(-1/8i)3(2i) in the form of a+ib

Answer 1

the ans to the ques is 0 - 3/4i

Answer 2

The required form is $(-i)(-\frac{1}{8}i)^3(2i)=0+\frac{1}{256}i$.

Step-by-step explanation:

Given : Expression $(-i)(-\frac{1}{8i})^3(2i)$

To find : Express the expression in the form of a+ib ?

Solution :

Solving the expression by multiplying the terms,

Expression $(-i)(-\frac{1}{8i})^3(2i)$

$(-i)(-\frac{1}{8}i)^3(2i)=(-2i^2)(-\frac{i^3}{8^3})$

We know that, $i^2=-1$

$(-i)(-\frac{1}{8}i)^3(2i)=(-2(-1))(-\frac{(-1)i}{512})$

$(-i)(-\frac{1}{8}i)^3(2i)=(2)(\frac{i}{512})$

$(-i)(-\frac{1}{8}i)^3(2i)=\frac{i}{256}$

Now, in form of a+ib

$(-i)(-\frac{1}{8}i)^3(2i)=0+\frac{1}{256}i$

Here, a=0 and $b=\frac{1}{256}$

#Learn more

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