Express the trigonometric ratio sin a sec a and tan a in terms of cot a
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tanA=sinA/cosA
cotA=cosA/sinA
therefore tanA=1/cotA
using the identity cosec^2A-cot^2A=1
we get cosec^2A=1+cot^2a
1/sin^2A=1+cot^2A
sin^2A=1/1+cot^2A
sinA=(1/1+cot^2A)^1/2
using identity sec^2A-tan^2A=1
we get
sec^2A=1+tan^2A
sec^2A=1+1/cot^2A
sec^2A=cot^2A+1/cot^2A
secA=(cot^2A+1/cot^2A)^1/2
PLS MARK BRAINLIEST
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