Math, asked by rakhijha0055, 11 days ago

Express the trigonometric ratios of secA and sinA in terms of tanA.

Answers

Answered by Rohit9935
1

Answer:

sec A = (1/cos A) = (1/√(1 - sin2 A)) and tan A = (sin A/cos A) = (sin A/√(1-sin2 A))

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