Express the trigonometric ratios of secA and sinA in terms of tanA.
Answers
Answered by
4
sec A = (1/cos A) = (1/√(1 - sin2 A)) and tan A = (sin A/cos A)
= (sin A/√(1-sin2 A))
hope it help uh dude
Answered by
22
question:
Express the trigonometric ratios of secA and sinA in terms of tanA.
Answer:
sec A = (1/cos A) = (1/√(1 - sin2 A)) and tan A = (sin A/cos A) = (sin A/√(1-sin2 A))
hope it helps you MR. jaat!!
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