express the trigonometric ratios of sin a and sec a in terms of cot a
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We have
1]cosec2A−cot2A=1
⇒cosec2A=1+cot2A
⇒(cosecA)2=cot2A+1
⇒(sinA1)2=cot2+1
⇒(sinA)2=cot2A+11
⇒sinA=±cot2A+11
We reject the negative value of sinA for acute angle A. Therefore sinA=cot2A+11
2]tanA=cotA1
3]We have sec2A−tan2A=1
⇒sec2A=1+tan2A
⇒sec2A=1+cot2
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