Express the trigonometric ratios of sinA and tanA in terms of secA?
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Answer:
tanA=
cotA
1
secA=
1+tan
2
A
=
1+
cot
2
A
1
sinA=
1−cos
2
A
=
1−
sec
2
A
1
=
1−
1+
cot
2
A
1
1
=
1−
1+cot
2
A
cot
2
A
sinA=
1+cot
2
A
1
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