express the trigonometric ratios sin A ,sec A and tan A in terms of cotA
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Answered by
2
sinA=cosA/cotA
secA=1/sinAcosA
tanA=1/cotA
secA=1/sinAcosA
tanA=1/cotA
Answered by
3
1.cotA=cosA/sinA
so sinA=cosA/cotA
2. secA=1/cosA
=1/(sinAcotA)
3.tanA=1/cotA
so sinA=cosA/cotA
2. secA=1/cosA
=1/(sinAcotA)
3.tanA=1/cotA
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