Question

Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.​

Answer 1

Answer:

SIN A 1) sinX=cos(90-X)

2) sinA=cos(90-A),cos(90-A)=1/cot(90-A), so sinA=1/cot(90-A)

SEC A ⇒secA=cotAcot2A+1.

We know that tan x is the ratio of sin x and cos x, cot x is the ratio of cos x and sin x. We can write sinθ=√1−cos2θ when sinθ is positive and sinθ is equal to −√1−cos2θ when sinθ is negative. tanθ−cotθ=−1−2cos2θ√1−cos2θcosθ ; θ∈(2n−1π,2nπ) - all the angles where cos is 0, n is an integer.

Answer 2

Answer:

here is your answer

Step-by-step explanation:

sinA= cosA/cotA= 1/secA CotA=1/✓(1+ tan^2A)cotA

convert tan to cot ok

secA= √1+ tan ^2A =√cot^2 A + 1/ cot^2A

tanA=1/cotA

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