Question

Express the trigonometric ratios sin A, secAand 10A in term of cotA

Answer 1

We all know that tan is reciprocal of cot a . (Cosec a )^2=1+cot^2a

Cosec a =(1+cot^2a)^1/2

And sin a =1/cosec a so sin a =1/1+cot^2a

Sec a =1+tan^2a so sec a will be under root 1+tan^2a.

sec a =(cot^2a+1)^(1/2)/(cot a)

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