express trigonometric ratios of acute angle cot (-3888)
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cot(-3888) = -cot(3888) = -cot(21π + 108 )
Hence - cot(21π + 108 ) = -cot(108)
As cot(nπ + x ) = cot(x)
-cot(108) = -cot(π/2 + 18 ) = -(-tan(18)) = tan18 (ans)
As in the second quadrant tan and cot is negative .
Answered by
9
cot(-3888)
-cot(3888)={2π×10+288}
=-cot (288)=-cot (180+108)
=-cot (108)=-cot (π\2+18)
=-(-tan18)
=tan18
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