Expression for instantaneous value of induced emf
Answers
Answered by
4
Here,
only the cosine component (which is perpendicular) imparts emf to the rotation coil.
So,
flux linkages of the coil will be
= number of turns in the coil × flux linking
φ = n × φmaxcoswt
now,
the emf will be
E = -d[φ]/dt
= -d/dt[n × φmaxcoswt]
thus,
E = n × φmaxw.sinwt
here maximum value of emf will be [for sinwt = 1]
Emax = n × φmaxw
thus,
we have
E = Emaxsinwt
or
E = Emaxsinθ
which is the instantaneous value of emf, continuously changing with time or angle.
now,
if θ = 360 degrees
sinθ = 0
thus,
we have
E = 0
only the cosine component (which is perpendicular) imparts emf to the rotation coil.
So,
flux linkages of the coil will be
= number of turns in the coil × flux linking
φ = n × φmaxcoswt
now,
the emf will be
E = -d[φ]/dt
= -d/dt[n × φmaxcoswt]
thus,
E = n × φmaxw.sinwt
here maximum value of emf will be [for sinwt = 1]
Emax = n × φmaxw
thus,
we have
E = Emaxsinwt
or
E = Emaxsinθ
which is the instantaneous value of emf, continuously changing with time or angle.
now,
if θ = 360 degrees
sinθ = 0
thus,
we have
E = 0
Attachments:
Similar questions
Math,
8 months ago
Math,
8 months ago
Social Sciences,
8 months ago
Hindi,
1 year ago
English,
1 year ago