expression of work done in moving a body down on inclined plane
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force × displacement
Anonymous:
.....wrong....
it says 'down on an inclined plane'
kkk ^_^
gm
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Suppose an object is pushed up a smooth inclined plane from ground level to a point h above the ground with force F. The angle of inclination is A. How much work is done?
To push an object up a smooth inclined plane, one must overcome the force of gravity which causes the object to slide down the plane. Hence, the force F=mgsinA must be applied. We can denote the distance the body undergoes as s=hsinA, then:
W=Fs=mg(sinA)^2
The answer is mgh and I know that this can be easily proven using energy conservation laws, but I want to know why my method is incorrect.
To push an object up a smooth inclined plane, one must overcome the force of gravity which causes the object to slide down the plane. Hence, the force F=mgsinA must be applied. We can denote the distance the body undergoes as s=hsinA, then:
W=Fs=mg(sinA)^2
The answer is mgh and I know that this can be easily proven using energy conservation laws, but I want to know why my method is incorrect.
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