Math, asked by ratnakarpathak7016, 7 months ago

Exterior angle, ACD of triangle is 100° and angle A and angle B are in the ratio 3:2 . Find all the angles

Answers

Answered by itsbiswaa
4

Answer:

Step-by-step explanation:

The sum of all the angles of a triangle is 180°.

Let the common ratio be x, then according to the question.

100°+3x°+2x°=180°

=>100°+5x°=180°

=>5x=80°

=>x=16°

Therefore,the angles are 100°,(16×3)=48°and (16×2)=32°

ANSWER-100°,48°and 32°

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Step-by-step explanation:

Answered by PeepingMoon
10

Answer:

The sum of all the angles of a triangle is 180°.

Let the common ratio be x, then according to the question.

100°+3x°+2x°=180°

=>100°+5x°=180°

=>5x=80°

=>x=16°

Therefore,the angles are 100°,(16×3)=48°and (16×2)=32°

ANSWER-100°,48°and 32°

Step-by-step explanation:

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