Question

Exterior angle,angleACD of a triangle is 100° and
angleA and angleB are in the ratio 3:2. Find all the
angles of the triangle.​

Answer 1

Step-by-step explanation:

The sum of all the angles of a triangle is 180°.

Let the common ratio be x, then according to the question.

100°+3x°+2x°=180°

=>100°+5x°=180°

=>5x=80°

=>x=16°

Therefore,the angles are 100°,(16×3)=48°and (16×2)=32°

ANSWER-100°,48°and 32°

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